【利用python进行数据分析】学习笔记-第7章 数据清洗和准备——处理缺失数据

第7章 数据清洗和准备

7.1 处理缺失数据

7.1.1 查看缺失数据


In [10]: string_data = pd.Series(['aardvark', 'artichoke', np.nan, 'avocado'])

In [11]: string_data
Out[11]:
0   aardvark
1  artichoke
2        NaN
3    avocado
dtype: object

In [12]: string_data.isnull()
Out[12]:
0  False
1  False
2   True
3  False
dtype: bool

In [13]: string_data[0] = None
In [14]: string_data.isnull()
Out[14]:
0   True
1  False
2   True
3  False
dtype: bool
  • 缺失数据处理的函数函数说明dropna根据各标签的值中是否存在缺失数据对轴标签进行过滤,可通过阈值调节对缺失值的容忍度fillna用指定值或插值方法(如ffill或bfill)填充缺失数据isnull返回一个含有布尔值的对象,这些布尔值表示哪些值是缺失值/NA,该对象的类型与源类型一样notnullisnull的否定式

7.1.2 滤除缺失数据


In [15]: from numpy import nan as NA

In [16]: data = pd.Series([1, NA, 3.5, NA, 7])

In [17]: data.dropna()
Out[17]:
0  1.0
2  3.5
4  7.0
dtype: float64

In [18]: data[data.notnull()]
Out[18]:
0  1.0
2  3.5
4  7.0
dtype: float64

In [19]: data = pd.DataFrame([[1., 6.5, 3.], [1., NA, NA],
   ....:                      [NA, NA, NA], [NA, 6.5, 3.]])

In [20]: cleaned = data.dropna()

In [21]: data
Out[21]:
     0    1    2
0  1.0  6.5  3.0
1  1.0  NaN  NaN
2  NaN  NaN  NaN
3  NaN  6.5  3.0

In [22]: cleaned
Out[22]:
     0    1    2
0  1.0  6.5  3.0

In [23]: data.dropna(how='all')
Out[23]:
     0    1    2
0  1.0  6.5  3.0
1  1.0  NaN  NaN
3  NaN  6.5  3.0

In [24]: data[4] = NA
In [25]: data
Out[25]:
     0    1    2    4
0  1.0  6.5  3.0  NaN
1  1.0  NaN  NaN  NaN
2  NaN  NaN  NaN  NaN
3  NaN  6.5  3.0  NaN

In [26]: data.dropna(axis=1, how='all')
Out[26]:
     0    1    2
0  1.0  6.5  3.0
1  1.0  NaN  NaN
2  NaN  NaN  NaN
3  NaN  6.5  3.0

In [27]: df = pd.DataFrame(np.random.randn(7, 3))

In [28]: df.iloc[:4, 1] = NA

In [29]: df.iloc[:2, 2] = NA

In [30]: df
Out[30]:
           0          1          2
0  -0.204708        NaN        NaN
1  -0.555730        NaN        NaN
2   0.092908        NaN   0.769023
3   1.246435        NaN  -1.296221
4   0.274992   0.228913   1.352917
5   0.886429  -2.001637  -0.371843
6   1.669025  -0.438570  -0.539741

In [31]: df.dropna()
Out[31]:
          0          1          2
4  0.274992   0.228913   1.352917
5  0.886429  -2.001637  -0.371843
6  1.669025  -0.438570  -0.539741

In [32]: df.dropna(thresh=2)
Out[32]:
          0          1          2
2  0.092908        NaN   0.769023
3  1.246435        NaN  -1.296221
4  0.274992   0.228913   1.352917
5  0.886429  -2.001637  -0.371843
6  1.669025  -0.438570  -0.539741

7.1.3 填充缺失数据


In [33]: df.fillna(0)
Out[33]:
           0          1          2
0  -0.204708   0.000000   0.000000
1  -0.555730   0.000000   0.000000
2   0.092908   0.000000   0.769023
3   1.246435   0.000000  -1.296221
4   0.274992   0.228913   1.352917
5   0.886429  -2.001637  -0.371843
6   1.669025  -0.438570  -0.539741

In [34]: df.fillna({1: 0.5, 2: 0})
Out[34]:
           0         1         2
0  -0.204708   0.500000   0.000000
1  -0.555730   0.500000   0.000000
2   0.092908   0.500000   0.769023
3   1.246435   0.500000  -1.296221
4   0.274992   0.228913   1.352917
5   0.886429  -2.001637  -0.371843
6   1.669025  -0.438570  -0.539741

In [37]: df = pd.DataFrame(np.random.randn(6, 3))

In [38]: df.iloc[2:, 1] = NA

In [39]: df.iloc[4:, 2] = NA

In [40]: df
Out[40]:
           0         1          2
0   0.476985  3.248944  -1.021228
1  -0.577087  0.124121   0.302614
2   0.523772       NaN   1.343810
3  -0.713544       NaN  -2.370232
4  -1.860761       NaN        NaN
5  -1.265934       NaN        NaN

In [41]: df.fillna(method='ffill')
Out[41]:
           0         1          2
0   0.476985  3.248944  -1.021228
1  -0.577087  0.124121   0.302614
2   0.523772  0.124121   1.343810
3  -0.713544  0.124121  -2.370232
4  -1.860761  0.124121  -2.370232
5  -1.265934  0.124121  -2.370232

In [42]: df.fillna(method='ffill', limit=2)
Out[42]:
           0         1          2
0   0.476985  3.248944  -1.021228
1  -0.577087  0.124121   0.302614
2   0.523772  0.124121   1.343810
3  -0.713544  0.124121  -2.370232
4  -1.860761       NaN  -2.370232
5  -1.265934       NaN  -2.370232

In [43]: data = pd.Series([1., NA, 3.5, NA, 7])
In [44]: data.fillna(data.mean())
Out[44]:
0  1.000000
1  3.833333
2  3.500000
3  3.833333
4  7.000000
dtype: float64
  • fillna函数的参数:参数说明value用于填充缺失值的标量值或字典对象method插值方式axis待填充的轴inplace修改调用者对象而不产生副本limit可以连续填充的最大数量

Original: https://blog.csdn.net/qq_51283283/article/details/115375696
Author: From Star.
Title: 【利用python进行数据分析】学习笔记-第7章 数据清洗和准备——处理缺失数据

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