题目如下
首先找到伤疤并提取出来，发现一共有256个数据，根据题目中的提示答案为32位的字符串，再根据伤疤只有两种状态22和44，联想到每8个伤疤拼成8位二进制，22表示0,44表示1，组成一个二进制串
0110110000101100000011000110110010011100101011000000110010000110101011000010110010001100000111000010110001000110001001101010110001100110101001100110110001000110011011001010011010101100010001100010110011000110101001100010110011001100000111001100110001001100
将这个二进制串每8位组成一个二进制数，并转为hex，将hex转为字符串输出，即可得到答案。
with open("E:\Download\misc\派大星的烦恼.bmp","rb") as fr:
res = fr.read()[4000:4256]
tmp = []
for v in res:
if v == 34:
tmp.append(0)
else:
tmp.append(1)
fr.close()
for i in range(len(tmp)):
tmp[i] = str(tmp[i])
a = "".join(tmp)
print(a)
b = []
for i in range(0,len(a),8):
b.append(int(a[i:i+8],2))
w = ""
for v in b:
w+=str(hex(v))[2:]
print(w)
<span class="ne-text">6c2cc6c9cacc86ac2c8c1c2c4626ac66a66c466ca6ac462cc6a62ccc1ccc4c</span>，发现这个hex串并不正确，无法解码，那么就将原本的二进制串逆序一下试试，
with open("E:\Download\misc\派大星的烦恼.bmp","rb") as fr:
res = fr.read()[4000:4256]
tmp = []
for v in res:
if v == 34:
tmp.append(0)
else:
tmp.append(1)
fr.close()
for i in range(len(tmp)):
tmp[i] = str(tmp[i])
a = "".join(tmp)
a = a[::-1]
print(a)
b = []
for i in range(0,len(a),8):
b.append(int(a[i:i+8],2))
w = ""
for v in b:
w+=str(hex(v))[2:]
print(w)
<span class="ne-text">3233383334656334623565366236656635646234383134356130353936303436</span>，
这个hex的结果 <span class="ne-text">23834ec4b5e6b6ef5db48145a0596046</span>提交不正确
那么可能是对每个二进制数据逆序，而不是整体逆序
with open("E:\Download\misc\派大星的烦恼.bmp","rb") as fr:
res = fr.read()[4000:4256]
tmp = []
for v in res:
if v == 34:
tmp.append(0)
else:
tmp.append(1)
fr.close()
for i in range(len(tmp)):
tmp[i] = str(tmp[i])
a = "".join(tmp)
print(a)
b = []
for i in range(0,len(a),8):
t = a[i:i+8]
t = t[::-1]
b.append(int(t,2))
w = ""
for v in b:
w+=str(hex(v))[2:]
print(w)
<span class="ne-text">3634303639353061353431383462643566653662366535623463653433383332</span>，
这个hex的结果 <span class="ne-text">6406950a54184bd5fe6b6e5b4ce43832</span>，提交成功
Original: https://www.cnblogs.com/WXjzc/p/16095984.html
Author: WXjzc
Title: buuctf 派大星的烦恼
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