1. 题目
Given three integers A, B and C in ((−2^{63},2^{63})), you are supposed to tell whether A+ B> C.
The first line of the input gives the positive number of test cases, T (≤10). Then T test cases follow, each consists of a single line containing three integers A, B and C, separated by single spaces.
For each test case, output in one line Case #X: true if A+ B> C, or Case #X: false otherwise, where X is the case number (starting from 1).
3
1 2 3
2 3 4
9223372036854775807 -9223372036854775808 0
Case #1: false
Case #2: true
Case #3: false
Thanks to Jiwen Lin for amending the test data.
2. 题意
输入a和b，判断a+b是否大于c。
3. 思路——简单模拟
4. 代码
方法1：
#include
#include
using namespace std;
typedef long long LL;
int main()
{
LL n;
LL a, b, c;
cin >> n;
for (int i = 1; i 0 && b > 0 && a + b < 0)
cout << "Case #" << i << ": true" << endl;
else if (a < 0 && b < 0 && a + b >= 0)
cout << "Case #" << i << ": false" << endl;
else if (a + b > c)
cout << "Case #" << i << ": true" << endl;
else cout << "Case #" << i << ": false" << endl;
}
return 0;
}
方法2：
#include
using namespace std;
typedef long long LL;s
typedef long double LD;
int main()
{
LL n;
LD a, b, c;
cin >> n;
for (int i = 1; i > a >> b >> c;
if (a + b > c)
cout << "Case #" << i << ": true" << endl;
else
cout << "Case #" << i << ": false" << endl;
}
return 0;
}
Original: https://www.cnblogs.com/vanishzeng/p/15478035.html
Author: vanish丶
Title: 1065 A+B and C (64bit) (20 分)
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