使用C# 7.0推出的值元组和解构功能。
static (int, int) Calc(int a, int b)
{
return (a + b, a - b);
}
static void Main()
{
var (add, sub) = Calc(8, 2);
Console.WriteLine($"{add}, {sub}");
}
Scala
使用元组。
def calc(a: Int, b: Int) : (Int, Int) = {
(a + b, a - b)
}
val (add, sub) = calc(8, 2)
println(s"$add, $sub")
Kotlin
使用Pair和解构声明。
fun calc(a: Int, b: Int): Pair<Int,Int> {
return Pair(a + b, a - b)
}
fun main() {
val (add, sub) = calc(8, 2)
println("$add, $sub")
}
使用数组和解构声明。
fun calc(a: Int, b: Int) : Array<Int> {
return arrayOf(a + b, a - b)
}
fun main() {
val (add, sub) = calc(8, 2)
println("$add, $sub")
}
JavaScript
使用解构赋值。
function calc(a, b) {
return [a + b, a - b];
}
let [add, sub] = calc(8, 2);
console.log(${add}, ${sub});
Python
使用元组和解构。
def calc(a, b):
return a + b, a - b
add, sub = calc(8, 2)
print(f"{add}, {sub}")
使用列表和解构。
def calc(a, b):
return [a + b, a - b]
add, sub = calc(8, 2)
print(f"{add}, {sub}")
Go
使用元组。
func calc(a int, b int) (int, int) {
return a + b, a - b
}
func main() {
add, sub := calc(8, 2)
fmt.Println(add, sub)
}
C++
使用元组和结构化绑定声明。
tuple<int, int> calc(int a, int b)
{
return make_tuple(a + b, a - b);
}
int main()
{
auto [add, sub] = calc(8, 2);
cout << add << ", " << sub << endl;
return 0;
}注意：
make_tuple不能写成 make_
tuple<int, int>(...), 要缺省掉模板参数，让编译器自动推导。msvc编译器会报错，编译不过。
#include#include #include std::tuple<int, int> f() // this function returns multiple values { int x = 5; return std::make_tuple(x, 7); // return {x,7}; in C++17 } int main() { // heterogeneous tuple construction int n = 1; auto t = std::make_tuple(10, "Test", 3.14, std::ref(n), n); n = 7; std::cout << "The value of t is " << "(" << std::get<0>(t) << ", " << std::get<1>(t) << ", " << std::get<2>(t) << ", " << std::get<3>(t) << ", " << std::get<4>(t) << ")\n"; // function returning multiple values int a, b; std::tie(a, b) = f(); std::cout << a << " " << b << "\n"; }
Ruby
使用解构赋值。
def calc(a, b)
return [a + b, a - b]
end
a, b = calc(8, 2)
puts "#{a}, #{b}"
Swift
func calc(a: Int, b: Int) -> (Int, Int) {
return (a + b, a - b)
}
let (add, sub) = calc(a:8, b:2)
print("\(add), \(sub)")
F
let calc a b =
a + b, a - b
[]
let main argv =
let add, sub = calc 8 2
printfn "%d, %d" add sub
0
Groovy
def calc(a, b) {
return [a + b, a - b]
}
def (add, sub) = calc(8, 2)
println("${add}, ${sub}")
Perl 6
sub calc($a, $b) {
return ($a + $b, $a - $b);
}
my ($add, $sub) = calc(8, 2);
print "$add, $sub";
Original: https://www.cnblogs.com/bigben0123/p/15748863.html
Author: Bigben
Title: js c++ 多值返回 返回多个值 c++ tuple
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