SQL语句实战学习

参考：https://zhuanlan.zhihu.com/p/38354000
再次感谢作者的整理！！

1.数据已提前准备好了，已知有如下4张表：
学生表：student

成绩表：score（学号，课程号，成绩）

课程表：course

教师表：teacher

2.1 简单查询

2.1.1 查询姓”曹”的学生名单

SELECT * FROM student WHERE name LIKE '曹%'

2.1.2 查询姓名中最后一个是”玉”的学生名单

SELECT * FROM student WHERE name LIKE '%玉'

2.1.3 查询姓名中带”星”的学生名单

SELECT * FROM student WHERE name LIKE '%星%'

2.2 汇总查询;

2.2.1 查询课程编号为”0002″的总成绩

SELECT SUM(grade) as '总成绩' FROM score WHERE course_id='0002'

2.2.2 查询选了课程的学生人数

SELECT COUNT(DISTINCT stu_id)  as '选了课程的学生人数' FROM score # DISTINCT  去重

2.3 分组查询

2.3.1 查询各科成绩最高和最低得分

SELECT MAX(grade) as '最高分',MIN(grade) as '最低分' FROM score ORDER BY grade

2.3.2 查询每门课程被选修的学生数

SELECT course_id as '课程号' ,COUNT(stu_id) as '学生人数' FROM score GROUP BY course_id

2.3.3 查询学生中男、女人数

SELECT sex,COUNT(sex) as '人数' FROM student GROUP BY sex

2.4 带条件的分组查询

2.4.1 查询平均成绩大于60分学生的学号和平均成绩

SELECT stu_id as '学号', AVG(grade) as '平均成绩' FROM score GROUP BY stu_id HAVING AVG(grade) > 60

2.4.2 查询至少选修两门课程的学生学号以及课程数目

SELECT stu_id as '学生学号', COUNT(course_id) as '课程数目' FROM score GROUP BY stu_id HAVING COUNT(course_id) > 2

2.4.3 查询同名同姓学生名单并统计同名人数

SELECT name as '学生名单' ,COUNT( name) as '同名人数' FROM student GROUP BY name

2.4.4 查询不及格的课程并按照课程号从大到小排序

SELECT course_id,grade from score WHERE grade < 85 ORDER BY grade DESC

2.4.5 查询每门课程的平均成绩，结果按照平均成绩升序排序，平均成绩相同时，按照课程好降序排序

SELECT course_id as '课程号',AVG(grade) as '平均成绩' from score GROUP BY course_id ORDER BY AVG(grade) and course_id

2.4.6 查询其中课程编号为”0003″且分数小于90的学生学号，结果按照分数降序排列

SELECT course_id , stu_id, grade from score WHERE course_id='0003' AND grade < 90 ORDER BY grade DESC

2.4.7 查询课程号和选修此课程人数，查询结果按照人数排序降序，若人数相同，按照课程号升序排序

SELECT course_id as '课程号', COUNT(course_id) as '课程人数' from score GROUP BY course_id ORDER BY COUNT(course_id) DESC,course_id ASC

2.4.8 查询两门以上成绩不满85分的同学的学号及其平均成绩

SELECT stu_id as '学号', AVG(grade) as '平均成绩' from score WHERE grade = 2

2.4.9 查询各科成绩前两名的记录

(SELECT *  from score WHERE course_id = '0001' ORDER BY grade DESC LIMIT 2) union
(SELECT *  from score WHERE course_id = '0002' ORDER BY grade DESC LIMIT 2) union
(SELECT *  from score WHERE course_id = '0003' ORDER BY grade DESC LIMIT 2);

2.5 汇总查询

2.5.1 查询学生的成绩并进行排名

SELECT stu_id , SUM(grade) FROM score GROUP BY stu_id ORDER BY SUM(grade)

2.5.2 查询平均成绩大于80分的学生的学号和平均成绩

SELECT stu_id ,AVG(grade) FROM score GROUP BY stu_id HAVING AVG(grade) > 80

2.5.3 查询所有课程成绩小于85分的学生的学号、姓名

SELECT id , name  FROM student WHERE  id in (SELECT stu_id  FROM score GROUP BY stu_id HAVING AVG(grade) < 85);

2.5.3 查询没有学全所有课程的学生的学号、姓名

SELECT id , name  FROM student WHERE  id in ( SELECT stu_id  FROM score GROUP BY stu_id HAVING COUNT(course_id) < 3);

2.5.4 查询1996年出生的学生名单

SELECT * FROM student WHERE year(brith) = 1996

2.5.5 查询各学生的年龄

SELECT id,name,TIMESTAMPDIFF(year,brith,now()) from student;

2.6 多表查询

2.6.1 查询所有学生的学号、姓名、选课数、总成绩

SELECT s1.id , s1.name, COUNT(s2.course_id) as 'count', SUM(grade) FROM student as s1 JOIN score as s2 WHERE s1.id = s2.stu_id GROUP BY s2.stu_id

2.6.2 查询平均成绩大于85分的所有学生的学号、姓名、平均成绩

SELECT s1.id , s1.name, AVG(grade) FROM student as s1 JOIN score as s2 WHERE s1.id = s2.stu_id GROUP BY s2.stu_id HAVING  AVG(grade) > 85

2.6.3 查询学生的选课情况：学号、姓名、课程号、课程名称

SELECT s1.id as '学号', s1.name as '姓名', s2.course_id as '课程号' ,c1.name as '课程名称' FROM student as s1 JOIN score as s2 JOIN course as c1 WHERE s1.id = s2.stu_id  and s2.course_id = c1.id;

2.6.4 查询出每门课程的大于80得人数和不大于80的人数

SELECT course_id, SUM(CASE WHEN grade > 80 THEN 1 ELSE 0 END) as '大于80', SUM(CASE WHEN grade '小于80' FROM score  GROUP BY course_id

2.6.5 使用分段[90,100],[80-90),[70,80),[60,70)区间统计各科成绩，统计各分段人数和，课程号，课程名称

SELECT s.course_id as '课程号',c1.name as '课程号',
sum(case when s.grade >= 60 and s.grade < 70 then 1 else 0 end) as '[60,70)',
sum(case when s.grade >= 70 and s.grade < 80 then 1 else 0 end) as '[70,80)',
sum(case when s.grade >= 80 and s.grade < 90 then 1 else 0 end) as '[80,90)',
sum(case when s.grade >= 90 and s.grade < 100 then 1 else 0 end) as '[90,100)'
from score as s join course as c1 where s.course_id = c1.id group by s.course_id;  

2.6.6. 查询课程编号为”0003″且课程成绩在90分以上的学生的学号和姓名

SELECT  s2.id as '学号',s2.name as '姓名'
from score as s1 join student as s2 where s1.stu_id = s2.id AND s1.course_id = '0003' AND s1.grade > 90;

2.6.7 数据的行列如何互换？

max()

2.7 多表连接查询

2.7.1 查询课程号为”0001″的课程分数小于90的学生信息，按照分数降序排列

select s2.id,s2.name,s1.course_id,s1.grade FROM score as s1 JOIN student as s2
WHERE s1.stu_id = s2.id AND s1.course_id = '0001' HAVING grade < 90 ORDER BY grade desc

2.7.2 查询不同老师所教的不同课程的平均分从高到低显示

select c1.teacher_id, s1.course_id, c1.name, avg(grade)
FROM score as s1 JOIN course as c1
WHERE s1.course_id = c1.id GROUP BY c1.teacher_id ORDER BY AVG( s1.grade) DESC

2.7.3 查询课程名称为”数学”，且分数低于90的学生姓名和分数

select s2.name as '学生姓名', s1.grade as '分数'
FROM score as s1 JOIN course as c1 JOIN student as s2
WHERE s1.course_id = c1.id AND s1.stu_id = s2.id
AND c1.name = '数学' and s1.grade < 90

2.7.4 查询两门及其以上课程小于85的同学的学号，姓名及其平均成绩

select s1.id as '学号',s1.name as '姓名',avg(s2.grade) as '平均成绩'
from student as s1 join score as s2 on s1.id = s2.stu_id and s2.grade < 85
group by s2.stu_id having count(s1.id) >= 2;

2.7.5 查询不同课程成绩相同的学生的学生编号、课程编号、学生成绩

SELECT
DISTINCT s1.stu_id as '学生编号', s1.course_id as '课程编号', s1.grade as '学生成绩'
FROM score AS s1 JOIN score AS s2
ON s1.stu_id = s2.stu_id
WHERE s1.course_id != s2.course_id  AND s1.grade = s2.grade

2.7.6 查询课程编号为”0002″的课程比”0001″的课程成绩高的所有学生的学号

SELECT
DISTINCT  a.stu_id,a.grade as '0002成绩',b.grade as '0001成绩'
FROM
(SELECT stu_id,grade FROM score WHERE course_id = '0002' ) as a
join
(SELECT stu_id,grade FROM score WHERE course_id = '0001' ) as b
ON a.stu_id = b.stu_id
where a.grade > b.grade;

2.7.7 查询学过编号为”0001″的课程并且也学过编号为”0002″的课程的学生的学号、姓名

SELECT
a.stu_id as '学号',s1.name as '姓名'
FROM
(SELECT stu_id FROM score WHERE course_id = '0002' ) as a
join
(SELECT stu_id FROM score WHERE course_id = '0001' ) as b
ON a.stu_id = b.stu_id
JOIN student as s1 on s1.id = b.stu_id

2.7.8 查询学过”陈独秀”老师所教的所有课的同学的学号、姓名

SELECT
DISTINCT s1.stu_id as '学号',s2.name as '姓名'
FROM
(SELECT course_id,t1.name FROM teacher as t1 JOIN score as s1 on t1.id = s1.course_id WHERE t1.name = '陈独秀') as a
join
score as s1
JOIN
student as s2
WHERE a.course_id = s1.course_id AND s1.stu_id = s2.id

2.7.9 查询至少有一门课与学号为”0001″的学生所学课程相同的学生的学号和姓名 </h4> <p><code>undefined</code></p> <p>SELECT s1.id,s1.<code>name</code> FROM student as s1 WHERE s1.id in (SELECT DISTINCT(stu_id) from score WHERE course_id in (SELECT course_id FROM score WHERE stu_id = '0001')) AND s1.id != '0001';</p> <p><code>undefined</code></p> <p><img alt="SQL语句实战学习" src="https://johngo-pic.oss-cn-beijing.aliyuncs.com/articles/20230524/2873222-20220723223239913-513587669.png" /></p> <h4>2.7.10 按平均成绩从高到低显示所有学生的所有课程的成绩以及平均成绩</h4> <pre><code>SELECT s1.stu_id as '学生号', MAX(CASE WHEN c1. = '语文' THEN s1.grade ELSE 0 END) as '语文', MAX(CASE WHEN c1. = '数学' THEN s1.grade ELSE 0 END) as '数学', MAX(CASE WHEN c1.` = ‘英语’ THEN s1.grade ELSE 0 END) as ‘英语’,
avg(s1.grade) as ‘平均成绩’
FROM course as c1 JOIN score as s1
ON c1.id = s1.course_id
GROUP BY s1.stu_id

Original: https://www.cnblogs.com/lxxduang/p/16512481.html
Author: 小小程序员-lian
Title: SQL语句实战学习