文章目录
一、中英文混合块加密算法
一、安装 numpy 包
方法如下：https://blog.csdn.net/weixin_45759918/article/details/124532318
二、需求
在英文块加密的基础上，完成中英文混合的块加密算法，中文字符从0x4e00开始，矩阵大小为145*145。
分析：这次的密码本需要多种形式组成，所以可以把字符先转为Unicode码的十进制形式再放入不同数组中。
密码本组成 = 中文Unicode字符 + 英文和标点Unicode字符 + 中文标点Unicode字符
145*145 = 20908 + 95 + 22
因为中文的标点符号在Unicode并不连续所以要单独列出来
其他的算法和加密英文没有区别，改改数就行。
注意：输入的字符有时有两个一样的内容（a=[‘人’,’人’]），加密解密时设置跳过相同字符，要不然加密解密都出错。
中文标点符号的列表
chinesePunctuationList = [183, 215, 8212, 8216, 8217, 8220, 8221, 8230, 12289, 12290, 12298, 12302, 12303, 12304,
12305, 65281, 65288, 65289, 65292, 65306, 65307, 65311]
可以参考这个图
三、参考答案
import numpy as np
def makeMatrix():
englishCharactersList = []
i = 32
while (i != 127):
englishCharactersList.append(i)
i += 1
chineseCharactersList = []
j = 19968
while (j != 40877):
chineseCharactersList.append(j)
j += 1
chinesePunctuationList = [183, 215, 8212, 8216, 8217, 8220, 8221, 8230, 12289, 12290, 12298, 12302, 12303, 12304,
12305, 65281, 65288, 65289, 65292, 65306, 65307, 65311]
allList = englishCharactersList + chineseCharactersList + chinesePunctuationList
data = np.random.choice(allList, size=21025, replace=False)
words = np.full((145, 145), 'k')
x = 0
for i in range(145):
for j in range(145):
words[i, j] = chr(int(data[x]))
x += 1
return words
def segmentationText(text):
textList = list(text)
if len(textList) % 2 != 0:
textList.append(" ")
data = []
for index in range(0, len(textList), 2):
data.append(textList[index:index + 2])
data = np.array(data)
return data
def encryption(words, data, text):
cipher = []
for i in range(len(data)):
A = data[i, 0]
B = data[i, 1]
Ax, Ay, Bx, By = 0, 0, 0, 0
if A == B:
cipher.append(A)
cipher.append(B)
continue
for x in range(145):
for y in range(145):
if words[x, y] == A:
Ax = int(x)
Ay = int(y)
elif words[x, y] == B:
Bx = int(x)
By = int(y)
if Ax == Bx or Ay == By:
A, B = B, A
else:
A = words[Bx, Ay]
B = words[Ax, By]
cipher.append(A)
cipher.append(B)
cipherStr = "".join(cipher)
print(f"原文为：{text}")
print(f"加密后文本为：{cipherStr}")
return cipher
def decryption(cipher, words, text):
cipherList = segmentationText(cipher)
clear = []
for i in range(len(cipherList)):
A = cipherList[i, 0]
B = cipherList[i, 1]
Ax, Ay, Bx, By = 0, 0, 0, 0
if A == B:
clear.append(A)
clear.append(B)
continue
for x in range(145):
for y in range(145):
if words[x, y] == A:
Ax = int(x)
Ay = int(y)
elif words[x, y] == B:
Bx = int(x)
By = int(y)
if Ax == Bx or Ay == By:
A, B = B, A
else:
A = words[Bx, Ay]
B = words[Ax, By]
clear.append(A)
clear.append(B)
clearStr = "".join(clear)
print(f"原文为：{text}")
print(f"解密为：{clearStr}")
text = input("请输入需要加密的字符串：")
words = makeMatrix()
data = segmentationText(text)
print(f"分割后数据为:\n{data}")
cipher = encryption(words, data, text)
decryption(cipher, words, text)
二、文本文件的块加密
一、安装 numpy 包
方法如下：https://blog.csdn.net/weixin_45759918/article/details/124532318
二、需求
增加了从文件中读取到写入文件的问题，并且要将文件名也加密，其实只是入口不一样了，别的没有变化。
在读文件时候注意把\n这个东西去掉，要不然保存出问题
注意！注意！注意！
需要加密的文件放在与py文件同一个文件夹下，这样可以直接写文件名，保存也会默认保存在这里。否则请使用绝对路径。
三、参考答案
import numpy as np
import os
def makeMatrix():
englishCharactersList = []
i = 32
while (i != 127):
englishCharactersList.append(i)
i += 1
chineseCharactersList = []
j = 19968
while (j != 40877):
chineseCharactersList.append(j)
j += 1
chinesePunctuationList = [183, 215, 8212, 8216, 8217, 8220, 8221, 8230, 12289, 12290, 12298, 12302, 12303, 12304,
12305, 65281, 65288, 65289, 65292, 65306, 65307, 65311]
allList = englishCharactersList + chineseCharactersList + chinesePunctuationList
data = np.random.choice(allList, size=21025, replace=False)
words = np.full((145, 145), 'k')
x = 0
for i in range(145):
for j in range(145):
words[i, j] = chr(int(data[x]))
x += 1
return words
def segmentationText(text):
textList = list(text)
if '\n' in textList:
x = 0
for i in range(len(textList)):
if i == "\n":
textList[x] == " "
x += 1
if len(textList) % 2 != 0:
textList.append(" ")
data = []
for index in range(0, len(textList), 2):
data.append(textList[index:index + 2])
data = np.array(data)
return data
def encryption(words, data, text):
cipher = []
for i in range(len(data)):
A = data[i, 0]
B = data[i, 1]
Ax, Ay, Bx, By = 0, 0, 0, 0
if A == B:
cipher.append(A)
cipher.append(B)
continue
for x in range(145):
for y in range(145):
if words[x, y] == A:
Ax = int(x)
Ay = int(y)
elif words[x, y] == B:
Bx = int(x)
By = int(y)
if Ax == Bx or Ay == By:
A, B = B, A
else:
A = words[Bx, Ay]
B = words[Ax, By]
cipher.append(A)
cipher.append(B)
cipherStr = "".join(cipher)
print(f"原文为：{text}")
print(f"加密后文本为：{cipherStr}")
return cipher
def decryption(cipher, words, text):
cipherList = segmentationText(cipher)
clear = []
for i in range(len(cipherList)):
A = cipherList[i, 0]
B = cipherList[i, 1]
Ax, Ay, Bx, By = 0, 0, 0, 0
if A == B:
clear.append(A)
clear.append(B)
continue
for x in range(145):
for y in range(145):
if words[x, y] == A:
Ax = int(x)
Ay = int(y)
elif words[x, y] == B:
Bx = int(x)
By = int(y)
if Ax == Bx or Ay == By:
A, B = B, A
else:
A = words[Bx, Ay]
B = words[Ax, By]
clear.append(A)
clear.append(B)
clearStr = "".join(clear)
print(f"原文为：{text}")
print(f"解密为：{clearStr}")
def readFile(fileName):
strs = ""
with open(fileName, 'r', encoding="UTF-8", newline=None) as file:
strs = file.read().splitlines()
st = "".join(strs)
return st
def writeFile(cipher, fileName, words):
encryptionFileName = str(fileName.split(".")[0])
fileNameData = segmentationText(encryptionFileName)
fileNamecipher = encryption(words, fileNameData, encryptionFileName)
st = "".join(fileNamecipher) + "." + fileName.split(".")[-1]
with open(st, "w", encoding="UTF-8") as op:
op.write("加密后文本为：" + "".join(cipher))
op.close()
os.system("notepad "+fileName+" && "+"notepad "+st)
fileName = input("请输入需要加密的文件名：")
text = readFile(fileName)
words = makeMatrix()
data = segmentationText(text)
print(f"分割后数据为:\n{data}")
cipher = encryption(words, data, text)
decryption(cipher, words, text)
writeFile(cipher, fileName, words)
四、例子
加密前：
加密后：
Original: https://blog.csdn.net/weixin_45759918/article/details/124575212
Author: 刘泳谦
Title: 【python】 中英文混合块加密算法&&文本文件的块加密
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