numpy.flip(m, axis=None)
-
Reverse the order of elements in an array along the given axis.
-
The shape of the array is preserved, but the elements are reordered.
-
New in version 1.12.0.
Parameters: m: array_like
- Input array.
axis: None or int or tuple of ints, optional
- Axis or axes along which to flip over. The default, axis=None, will flip over all of the axes of the input array. If axis is negative it counts from the last to the first axis.
If axis is a tuple of ints, flipping is performed on all of the axes specified in the tuple.
Changed in version 1.15.0: None and tuples of axes are supported
Returns
outarray_like
A view of m with the entries of axis reversed. Since a view is returned, this operation is done in constant time.
flip(m, 0) is equivalent to flipud(m).
flip(m, 1) is equivalent to fliplr(m).
flip(m, n) corresponds to m[...,::-1,...] with ::-1 at position n.
flip(m) corresponds to m[::-1,::-1,...,::-1] with ::-1 at all positions.
flip(m, (0, 1)) corresponds to m[::-1,::-1,...] with ::-1 at position 0 and position 1.
Examples
A = np.arange(8).reshape((2,2,2))
A
array([[[0, 1],
[2, 3]],
[[4, 5],
[6, 7]]])
np.flip(A, 0)
array([[[4, 5],
[6, 7]],
[[0, 1],
[2, 3]]])
np.flip(A, 1)
array([[[2, 3],
[0, 1]],
[[6, 7],
[4, 5]]])
np.flip(A)
array([[[7, 6],
[5, 4]],
[[3, 2],
[1, 0]]])
np.flip(A, (0, 2))
array([[[5, 4],
[7, 6]],
[[1, 0],
[3, 2]]])
A = np.random.randn(3,4,5)
np.all(np.flip(A,2) == A[:,:,::-1,...])
True
Original: https://blog.csdn.net/juluwangriyue/article/details/119973601
Author: 落花逐流水
Title: numpy矩阵反转 np.flip()
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