print(ss['time'])
0 2014-01-21 03:31:11
1 2014-01-21 04:53:55
2 2014-01-21 05:16:18
3 2014-01-21 05:55:05
4 2014-01-21 08:44:53
ss['date_30s'] = pd.to_datetime(ss['time'].apply(lambda x: time.strftime("%Y-%m-%d %H:%M:%S",time.localtime(int(x.timestamp()/30)*30) )))
ss['date_30s']
0 2014-01-21 11:31:00
1 2014-01-21 12:53:30
2 2014-01-21 13:16:00
3 2014-01-21 13:55:00
4 2014-01-21 16:44:30
Name: date_30s, dtype: datetime64[ns]
Original: https://blog.csdn.net/huochuangchuang/article/details/114380557
Author: mengzhongjack
Title: pandas DataFrame 按照30s 向下取整
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