1.前言
[TencentCloudSDKException] code:FailedOperation.ServiceIsolate message:service is stopped due to arrears, please recharge your account in Tencent Cloud requestId:3515dfde-2780-422e-a713-e67d423a1e55
[En]
[TencentCloudSDKException] code:FailedOperation.ServiceIsolate message:service is stopped due to arrears, please recharge your account in Tencent Cloud requestId:2c25383f-199a-47ad-aa7e-87d3757dce51
2.思路
选择排序重在 选择二字,比如给定一串数字 5 3 4 1 2,我们选定第一位存放最小的数字,因此需要找出数字5后面所有数字 3 4 1 2中最小的数字与其交换,以此类推再完成第二个第三个直到最后一位。
3.代码
4.分析
选择排序的每一次选中最小值都需要经过N-m次循环,N为数组的总长度,m为当前排序的位置。
[TencentCloudSDKException] code:FailedOperation.ServiceIsolate message:service is stopped due to arrears, please recharge your account in Tencent Cloud requestId:d0919fcd-1133-43f7-83d0-64c005a69216
[En]
[TencentCloudSDKException] code:FailedOperation.ServiceIsolate message:service is stopped due to arrears, please recharge your account in Tencent Cloud requestId:58d63403-6625-440f-93b3-18fee336ebb9
最好情况:(N-1)+(N-2)+ … + 2 + 1 = N(N-1)/2 次
最坏情况:(N-1)+(N-2)+ … + 2 + 1 = N(N-1)/2 次
时间复杂度:O(n²)
空间复杂度:O(1)
Original: https://www.cnblogs.com/anlizhaomi/p/16249612.html
Author: 暗里&着迷
Title: 【JAVA】排序算法之选择排序
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