Outline
lis = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
从lis中每次取两个元素,且所取不重复:
[1, 2]
[3, 4]
[5, 6]
[7, 8]
[9, 10]
实现
method1
ret = []
a = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
for i in range(0,len(a), 2):
ret.append(a[i:i+2])
print(a[i:i+2])
# [1, 2]
# [3, 4]
# [5, 6]
# [7, 8]
# [9, 10]
method2
a = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
for r in [a[i:i + 2] for i in range(0, len(a), 2)]: # 列表生成式
print(r)
# [1, 2]
# [3, 4]
# [5, 6]
# [7, 8]
# [9, 10]
Original: https://www.cnblogs.com/bigtreei/p/14452863.html
Author: ZhuGaochao
Title: Python for 循环每次取列表中指定个数元素
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